Two cells in a unit share exactly two candidates; those digits are eliminated from all other cells in the unit.
When exactly two cells in a unit (row, column, or box) share exactly the same two candidates (e.g. {3,7} and {3,7}), those two digits must occupy those two cells. Therefore 3 and 7 can be eliminated from all other cells in that unit.
This relies on the "locking" principle: two values occupy two cells.
46 | 79 | |||||||
247 | 147 | |||||||
17 | 24 | |||||||
49 | 37 | |||||||
147 | 47 | 247 | 457 | 3 | 467 | 479 | 47 | 478 |
48 | 57 | |||||||
24 | 78 | |||||||
147 | 467 | |||||||
37 | 24 |
Row 4: R4C2={3,7}, R4C8={3,7} → 3 and 7 can be eliminated from all other cells in row 4.
This 9×9 puzzle is solver-verified to require this technique on its solution path.