A conjugate pair in a row and one in a column intersect in a box; cells seeing both free ends can have the digit eliminated.
For a digit, a conjugate pair exists in one row and another in one column. If one end of each pair is in the same box, the two free ends form a virtual conjugate pair. Any cell seeing both free ends can have the digit eliminated.
| 4 | 58 | 36 | 9 | 1 | 58 | 2 | 36 | 7 |
15 | 2 | 36 | 4 | 56 | 7 | 136 | 8 | 9 |
| 7 | 18 | 9 | 2 | 3 | 68 | 16 | 4 | 5 |
| 2 | 6 | 1 | 58 | 58 | 3 | 9 | 7 | 4 |
| 8 | 7 | 4 | 1 | 9 | 2 | 36 | 5 | 36 |
| 3 | 9 | 5 | 6 | 7 | 4 | 8 | 1 | 2 |
56 | 35 | 2 | 7 | 68 | 1 | 4 | 9 | 368 |
169 | 13 | 7 | 38 | 4 | 69 | 5 | 2 | 1368 |
169 | 4 | 8 | 35 | 2 | 569 | 7 | 36 | 136 |
This 9×9 puzzle is solver-verified to require this technique on its solution path.